Base | Representation |
---|---|
bin | 1010010011100011010110… |
… | …0011110100111010101011 |
3 | 1111010020100102112101121002 |
4 | 2210320311203310322223 |
5 | 2441121413202423313 |
6 | 40033222204305215 |
7 | 2246432203331426 |
oct | 244706543647253 |
9 | 44106312471532 |
10 | 11331022311083 |
11 | 3679506771732 |
12 | 133004054220b |
13 | 642684367247 |
14 | 2b25d27da9bd |
15 | 149b2c5ce058 |
hex | a4e358f4eab |
11331022311083 has 2 divisors, whose sum is σ = 11331022311084. Its totient is φ = 11331022311082.
The previous prime is 11331022311079. The next prime is 11331022311101. The reversal of 11331022311083 is 38011322013311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331022311083 - 22 = 11331022311079 is a prime.
It is a super-4 number, since 4×113310223110834 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11331022311053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665511155541 + 5665511155542.
It is an arithmetic number, because the mean of its divisors is an integer number (5665511155542).
Almost surely, 211331022311083 is an apocalyptic number.
11331022311083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331022311083 is an equidigital number, since it uses as much as digits as its factorization.
11331022311083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 11331022311083 its reverse (38011322013311), we get a palindrome (49342344324394).
The spelling of 11331022311083 in words is "eleven trillion, three hundred thirty-one billion, twenty-two million, three hundred eleven thousand, eighty-three".
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