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11331033113 is a prime number
BaseRepresentation
bin10101000110110000…
…11101100000011001
31002020200100010022002
422203120131200121
5141201221024423
65112211210345
7550536122651
oct124330354031
932220303262
1011331033113
114895088984
1222428a69b5
1310b769c72a
14796c41361
15464b7d228
hex2a361d819

11331033113 has 2 divisors, whose sum is σ = 11331033114. Its totient is φ = 11331033112.

The previous prime is 11331033089. The next prime is 11331033139. The reversal of 11331033113 is 31133013311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10776100864 + 554932249 = 103808^2 + 23557^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331033113 is a prime.

It is a super-2 number, since 2×113310331132 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (11331033163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665516556 + 5665516557.

It is an arithmetic number, because the mean of its divisors is an integer number (5665516557).

Almost surely, 211331033113 is an apocalyptic number.

It is an amenable number.

11331033113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331033113 is an equidigital number, since it uses as much as digits as its factorization.

11331033113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 11331033113 its reverse (31133013311), we get a palindrome (42464046424).

The spelling of 11331033113 in words is "eleven billion, three hundred thirty-one million, thirty-three thousand, one hundred thirteen".