11331100103113 has 4 divisors (see below), whose sum is σ = 12949828689280. Its totient is φ = 9712371516948.

The previous prime is 11331100103101. The next prime is 11331100103119. The reversal of 11331100103113 is 31130100113311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11331100103113 - 2²⁹ = 11330563232201 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11331100103119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 809364293073 + ... + 809364293086.

It is an arithmetic number, because the mean of its divisors is an integer number (3237457172320).

Almost surely, 2^{11331100103113} is an apocalyptic number.

It is an amenable number.

11331100103113 is a deficient number, since it is larger than the sum of its proper divisors (1618728586167).

11331100103113 is an equidigital number, since it uses as much as digits as its factorization.

11331100103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1618728586166.

The product of its (nonzero) digits is 81, while the sum is 19.

Adding to 11331100103113 its reverse (31130100113311), we get a palindrome (42461200216424).

The spelling of 11331100103113 in words is "eleven trillion, three hundred thirty-one billion, one hundred million, one hundred three thousand, one hundred thirteen".