Base | Representation |
---|---|
bin | 1010010011100011101001… |
… | …1011001110111110010001 |
3 | 1111010020120010010210201102 |
4 | 2210320322123032332101 |
5 | 2441122100102211333 |
6 | 40033234242114145 |
7 | 2246434214240126 |
oct | 244707233167621 |
9 | 44106503123642 |
10 | 11331103944593 |
11 | 3679548859144 |
12 | 133006394b955 |
13 | 642698249cb4 |
14 | 2b25dd5aa74d |
15 | 149b34856ae8 |
hex | a4e3a6cef91 |
11331103944593 has 2 divisors, whose sum is σ = 11331103944594. Its totient is φ = 11331103944592.
The previous prime is 11331103944581. The next prime is 11331103944607. The reversal of 11331103944593 is 39544930113311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10838732281729 + 492371662864 = 3292223^2 + 701692^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331103944593 - 210 = 11331103943569 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331103944893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665551972296 + 5665551972297.
It is an arithmetic number, because the mean of its divisors is an integer number (5665551972297).
Almost surely, 211331103944593 is an apocalyptic number.
It is an amenable number.
11331103944593 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331103944593 is an equidigital number, since it uses as much as digits as its factorization.
11331103944593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 524880, while the sum is 47.
The spelling of 11331103944593 in words is "eleven trillion, three hundred thirty-one billion, one hundred three million, nine hundred forty-four thousand, five hundred ninety-three".
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