Base | Representation |
---|---|
bin | 1010010011100011101101… |
… | …1100110010111100100111 |
3 | 1111010020121022110222110020 |
4 | 2210320323130302330213 |
5 | 2441122114002200203 |
6 | 40033240054330223 |
7 | 2246434513311141 |
oct | 244707334627447 |
9 | 44106538428406 |
10 | 11331121131303 |
11 | 3679557527836 |
12 | 1330069659973 |
13 | 64269b986a4c |
14 | 2b26019a1c91 |
15 | 149b360ee153 |
hex | a4e3b732f27 |
11331121131303 has 16 divisors (see below), whose sum is σ = 15127315632000. Its totient is φ = 7544508570144.
The previous prime is 11331121131241. The next prime is 11331121131347. The reversal of 11331121131303 is 30313112113311.
It is not a de Polignac number, because 11331121131303 - 28 = 11331121131047 is a prime.
It is a super-2 number, since 2×113311211313032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331121131373) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8714448 + ... + 9929946.
It is an arithmetic number, because the mean of its divisors is an integer number (945457227000).
Almost surely, 211331121131303 is an apocalyptic number.
11331121131303 is a deficient number, since it is larger than the sum of its proper divisors (3796194500697).
11331121131303 is a wasteful number, since it uses less digits than its factorization.
11331121131303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1219438.
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 11331121131303 its reverse (30313112113311), we get a palindrome (41644233244614).
The spelling of 11331121131303 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-one million, one hundred thirty-one thousand, three hundred three".
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