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11331122001113 = 107105898336459
BaseRepresentation
bin1010010011100011101110…
…0000000111010011011001
31111010020121101010011121102
42210320323200013103121
52441122114213013423
640033240125121145
72246434523563055
oct244707340072331
944106541104542
1011331122001113
113679557a71292
1213300699b91b5
1364269bbcc925
142b2601b4ac65
15149b36221c28
hexa4e3b8074d9

11331122001113 has 4 divisors (see below), whose sum is σ = 11437020337680. Its totient is φ = 11225223664548.

The previous prime is 11331122001071. The next prime is 11331122001137. The reversal of 11331122001113 is 31110022113311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11331122001113 - 212 = 11331121997017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11331122009113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52949168123 + ... + 52949168336.

It is an arithmetic number, because the mean of its divisors is an integer number (2859255084420).

Almost surely, 211331122001113 is an apocalyptic number.

It is an amenable number.

11331122001113 is a deficient number, since it is larger than the sum of its proper divisors (105898336567).

11331122001113 is a wasteful number, since it uses less digits than its factorization.

11331122001113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105898336566.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 11331122001113 its reverse (31110022113311), we get a palindrome (42441144114424).

The spelling of 11331122001113 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-two million, one thousand, one hundred thirteen".

Divisors: 1 107 105898336459 11331122001113