Base | Representation |
---|---|
bin | 1010010011100011101111… |
… | …1110101011000111011010 |
3 | 1111010020121221012011122110 |
4 | 2210320323332223013122 |
5 | 2441122123240341442 |
6 | 40033241012533150 |
7 | 2246434651636554 |
oct | 244707376530732 |
9 | 44106557164573 |
10 | 11331130012122 |
11 | 3679561543058 |
12 | 13300706211b6 |
13 | 6426a077607b |
14 | 2b2602c344d4 |
15 | 149b36ca569c |
hex | a4e3bfab1da |
11331130012122 has 64 divisors (see below), whose sum is σ = 23697563996160. Its totient is φ = 3605190773184.
The previous prime is 11331130012087. The next prime is 11331130012123. The reversal of 11331130012122 is 22121003113311.
It is a super-2 number, since 2×113311300121222 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11331130012123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 290828079 + ... + 290867037.
It is an arithmetic number, because the mean of its divisors is an integer number (370274437440).
Almost surely, 211331130012122 is an apocalyptic number.
11331130012122 is an abundant number, since it is smaller than the sum of its proper divisors (12366433984038).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11331130012122 is a wasteful number, since it uses less digits than its factorization.
11331130012122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43387.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 11331130012122 its reverse (22121003113311), we get a palindrome (33452133125433).
The spelling of 11331130012122 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty million, twelve thousand, one hundred twenty-two".
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