Base | Representation |
---|---|
bin | 1010010011100011101111… |
… | …1110101101010101100011 |
3 | 1111010020121221012122010101 |
4 | 2210320323332231111203 |
5 | 2441122123241134334 |
6 | 40033241013043231 |
7 | 2246434652005231 |
oct | 244707376552543 |
9 | 44106557178111 |
10 | 11331130021219 |
11 | 3679561549978 |
12 | 1330070626517 |
13 | 6426a077a258 |
14 | 2b2602c37951 |
15 | 149b36ca8214 |
hex | a4e3bfad563 |
11331130021219 has 2 divisors, whose sum is σ = 11331130021220. Its totient is φ = 11331130021218.
The previous prime is 11331130021163. The next prime is 11331130021223. The reversal of 11331130021219 is 91212003113311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331130021219 - 229 = 11330593150307 is a prime.
It is a super-2 number, since 2×113311300212192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11331130021229) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565010609 + 5665565010610.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565010610).
Almost surely, 211331130021219 is an apocalyptic number.
11331130021219 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331130021219 is an equidigital number, since it uses as much as digits as its factorization.
11331130021219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 28.
The spelling of 11331130021219 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty million, twenty-one thousand, two hundred nineteen".
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