11331131210121 has 4 divisors (see below), whose sum is σ = 15108174946832. Its totient is φ = 7554087473412.

The previous prime is 11331131210111. The next prime is 11331131210219. The reversal of 11331131210121 is 12101213113311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2^k-11331131210121 is a prime.

It is a super-3 number, since 3×11331131210121³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11331131210101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1888521868351 + ... + 1888521868356.

It is an arithmetic number, because the mean of its divisors is an integer number (3777043736708).

Almost surely, 2^{11331131210121} is an apocalyptic number.

It is an amenable number.

11331131210121 is a deficient number, since it is larger than the sum of its proper divisors (3777043736711).

11331131210121 is an equidigital number, since it uses as much as digits as its factorization.

11331131210121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3777043736710.

The product of its (nonzero) digits is 108, while the sum is 21.

Adding to 11331131210121 its reverse (12101213113311), we get a palindrome (23432344323432).

The spelling of 11331131210121 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, two hundred ten thousand, one hundred twenty-one".