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113311313131 = 432635146817
BaseRepresentation
bin110100110000111100…
…0010110110011101011
3101211110212020010001011
41221201320112303223
53324030144010011
6124015434404351
711120650161412
oct1514170266353
9354425203034
10113311313131
1144067311735
1219b638906b7
13a8ba5406a3
1456acca6479
152e32b82621
hex1a61e16ceb

113311313131 has 4 divisors (see below), whose sum is σ = 115946459992. Its totient is φ = 110676166272.

The previous prime is 113311313033. The next prime is 113311313153. The reversal of 113311313131 is 131313113311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113311313131 - 215 = 113311280363 is a prime.

It is a super-2 number, since 2×1133113131312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113311313191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1317573366 + ... + 1317573451.

It is an arithmetic number, because the mean of its divisors is an integer number (28986614998).

Almost surely, 2113311313131 is an apocalyptic number.

113311313131 is a deficient number, since it is larger than the sum of its proper divisors (2635146861).

113311313131 is an equidigital number, since it uses as much as digits as its factorization.

113311313131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2635146860.

The product of its digits is 243, while the sum is 22.

Adding to 113311313131 its reverse (131313113311), we get a palindrome (244624426442).

The spelling of 113311313131 in words is "one hundred thirteen billion, three hundred eleven million, three hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 43 2635146817 113311313131