Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011101010011101001011 |
3 | 1111010020122000122121220112 |
4 | 2210320330003222131023 |
5 | 2441122124104221024 |
6 | 40033241100544535 |
7 | 2246434666025201 |
oct | 244707403523513 |
9 | 44106560577815 |
10 | 11331131320139 |
11 | 3679562256864 |
12 | 1330070b5214b |
13 | 6426a0b13547 |
14 | 2b2603095071 |
15 | 149b36e6300e |
hex | a4e3c0ea74b |
11331131320139 has 2 divisors, whose sum is σ = 11331131320140. Its totient is φ = 11331131320138.
The previous prime is 11331131320037. The next prime is 11331131320189. The reversal of 11331131320139 is 93102313113311.
11331131320139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331131320139 - 28 = 11331131319883 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331131320189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565660069 + 5665565660070.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565660070).
Almost surely, 211331131320139 is an apocalyptic number.
11331131320139 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331131320139 is an equidigital number, since it uses as much as digits as its factorization.
11331131320139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4374, while the sum is 32.
The spelling of 11331131320139 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred twenty thousand, one hundred thirty-nine".
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