Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0110010000110000110010 |
3 | 1111010020122001221020022211 |
4 | 2210320330012100300302 |
5 | 2441122124243020310 |
6 | 40033241123322334 |
7 | 2246435004563161 |
oct | 244707406206062 |
9 | 44106561836284 |
10 | 11331132001330 |
11 | 3679562681629 |
12 | 13300712203aa |
13 | 6426a0cc160b |
14 | 2b26031d13d8 |
15 | 149b37049c8a |
hex | a4e3c190c32 |
11331132001330 has 32 divisors (see below), whose sum is σ = 20522970768240. Its totient is φ = 4504318606080.
The previous prime is 11331132001327. The next prime is 11331132001331. The reversal of 11331132001330 is 3310023113311.
It can be written as a sum of positive squares in 8 ways, for example, as 10087668379881 + 1243463621449 = 3176109^2 + 1115107^2 .
It is a super-2 number, since 2×113311320013302 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (11331132001331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3334209 + ... + 5811988.
Almost surely, 211331132001330 is an apocalyptic number.
11331132001330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11331132001330 is a deficient number, since it is larger than the sum of its proper divisors (9191838766910).
11331132001330 is a wasteful number, since it uses less digits than its factorization.
11331132001330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9146974.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 11331132001330 its reverse (3310023113311), we get a palindrome (14641155114641).
The spelling of 11331132001330 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, one thousand, three hundred thirty".
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