Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0110010101101001001011 |
3 | 1111010020122001222020202022 |
4 | 2210320330012111221023 |
5 | 2441122124244140243 |
6 | 40033241123555055 |
7 | 2246435005005362 |
oct | 244707406255113 |
9 | 44106561866668 |
10 | 11331132021323 |
11 | 3679562695654 |
12 | 133007122ba8b |
13 | 6426a0cca74a |
14 | 2b26031d87d9 |
15 | 149b37050b68 |
hex | a4e3c195a4b |
11331132021323 has 2 divisors, whose sum is σ = 11331132021324. Its totient is φ = 11331132021322.
The previous prime is 11331132021301. The next prime is 11331132021343. The reversal of 11331132021323 is 32312023113311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331132021323 - 226 = 11331064912459 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 11331132021292 and 11331132021301.
It is not a weakly prime, because it can be changed into another prime (11331132021343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566010661 + 5665566010662.
It is an arithmetic number, because the mean of its divisors is an integer number (5665566010662).
Almost surely, 211331132021323 is an apocalyptic number.
11331132021323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331132021323 is an equidigital number, since it uses as much as digits as its factorization.
11331132021323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 11331132021323 its reverse (32312023113311), we get a palindrome (43643155134634).
The spelling of 11331132021323 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, twenty-one thousand, three hundred twenty-three".
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