Base | Representation |
---|---|
bin | 110100110000111101… |
… | …1000110001001100011 |
3 | 101211110220120121020011 |
4 | 1221201323012021203 |
5 | 3324030340000311 |
6 | 124015502025351 |
7 | 11120656242322 |
oct | 1514173061143 |
9 | 354426517204 |
10 | 113312031331 |
11 | 44067762294 |
12 | 19b63b78257 |
13 | a8ba732565 |
14 | 56ad0120b9 |
15 | 2e32c75321 |
hex | 1a61ec6263 |
113312031331 has 2 divisors, whose sum is σ = 113312031332. Its totient is φ = 113312031330.
The previous prime is 113312031293. The next prime is 113312031347. The reversal of 113312031331 is 133130213311.
It is a strong prime.
It is an emirp because it is prime and its reverse (133130213311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113312031331 - 229 = 112775160419 is a prime.
It is a super-2 number, since 2×1133120313312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113312031361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656015665 + 56656015666.
It is an arithmetic number, because the mean of its divisors is an integer number (56656015666).
Almost surely, 2113312031331 is an apocalyptic number.
113312031331 is a deficient number, since it is larger than the sum of its proper divisors (1).
113312031331 is an equidigital number, since it uses as much as digits as its factorization.
113312031331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 113312031331 its reverse (133130213311), we get a palindrome (246442244642).
The spelling of 113312031331 in words is "one hundred thirteen billion, three hundred twelve million, thirty-one thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •