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113312113122001 = 479236559735119
BaseRepresentation
bin11001110000111010001000…
…010000000101101011010001
3112212012112100222201102212111
4121300322020100011223101
5104323001201424401001
61040554511030425321
732603346536526643
oct3160721020055321
9485175328642774
10113312113122001
11331174408a8aa2
1210860791502241
134b2c395350b71
141dda49aa02893
15d17794c7d851
hex670e88405ad1

113312113122001 has 4 divisors (see below), whose sum is σ = 113548672857600. Its totient is φ = 113075553386404.

The previous prime is 113312113121993. The next prime is 113312113122017. The reversal of 113312113122001 is 100221311213311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113312113122001 - 23 = 113312113121993 is a prime.

It is a super-3 number, since 3×1133121131220013 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113312113152001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118279867081 + ... + 118279868038.

It is an arithmetic number, because the mean of its divisors is an integer number (28387168214400).

Almost surely, 2113312113122001 is an apocalyptic number.

It is an amenable number.

113312113122001 is a deficient number, since it is larger than the sum of its proper divisors (236559735599).

113312113122001 is an equidigital number, since it uses as much as digits as its factorization.

113312113122001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 236559735598.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 113312113122001 its reverse (100221311213311), we get a palindrome (213533424335312).

The spelling of 113312113122001 in words is "one hundred thirteen trillion, three hundred twelve billion, one hundred thirteen million, one hundred twenty-two thousand, one".

Divisors: 1 479 236559735119 113312113122001