Base | Representation |
---|---|
bin | 11001110000111011000100… |
… | …011100111110011001010001 |
3 | 112212012121222101020022111121 |
4 | 121300323010130332121101 |
5 | 104323010234010224014 |
6 | 1040555155150442241 |
7 | 32603413552504312 |
oct | 3160730434763121 |
9 | 485177871208447 |
10 | 113313123133009 |
11 | 33117909a3a238 |
12 | 10860a13803381 |
13 | 4b2c4c6684907 |
14 | 1dda554bd8609 |
15 | d1780378b124 |
hex | 670ec473e651 |
113313123133009 has 2 divisors, whose sum is σ = 113313123133010. Its totient is φ = 113313123133008.
The previous prime is 113313123132997. The next prime is 113313123133033. The reversal of 113313123133009 is 900331321313311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96234079150609 + 17079043982400 = 9809897^2 + 4132680^2 .
It is a cyclic number.
It is not a de Polignac number, because 113313123133009 - 25 = 113313123132977 is a prime.
It is not a weakly prime, because it can be changed into another prime (113313123433009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656561566504 + 56656561566505.
It is an arithmetic number, because the mean of its divisors is an integer number (56656561566505).
Almost surely, 2113313123133009 is an apocalyptic number.
It is an amenable number.
113313123133009 is a deficient number, since it is larger than the sum of its proper divisors (1).
113313123133009 is an equidigital number, since it uses as much as digits as its factorization.
113313123133009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 34.
The spelling of 113313123133009 in words is "one hundred thirteen trillion, three hundred thirteen billion, one hundred twenty-three million, one hundred thirty-three thousand, nine".
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