Search a number
-
+
11331312331993 is a prime number
BaseRepresentation
bin1010010011100100011011…
…0110001010110011011001
31111010021002122020222111021
42210321012312022303121
52441123011424110433
640033311044402441
72246442324426433
oct244710666126331
944107078228437
1011331312331993
11367964544a735
1213301016a6421
136426cc47cb54
142b261d133653
15149b47cbb22d
hexa4e46d8acd9

11331312331993 has 2 divisors, whose sum is σ = 11331312331994. Its totient is φ = 11331312331992.

The previous prime is 11331312331981. The next prime is 11331312332003. The reversal of 11331312331993 is 39913321313311.

11331312331993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6064851886864 + 5266460445129 = 2462692^2 + 2294877^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331312331993 is a prime.

It is not a weakly prime, because it can be changed into another prime (11331352331993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665656165996 + 5665656165997.

It is an arithmetic number, because the mean of its divisors is an integer number (5665656165997).

Almost surely, 211331312331993 is an apocalyptic number.

It is an amenable number.

11331312331993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331312331993 is an equidigital number, since it uses as much as digits as its factorization.

11331312331993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 118098, while the sum is 43.

The spelling of 11331312331993 in words is "eleven trillion, three hundred thirty-one billion, three hundred twelve million, three hundred thirty-one thousand, nine hundred ninety-three".