Base | Representation |
---|---|
bin | 1010010011100100011101… |
… | …0011100010101100010111 |
3 | 1111010021010011202011221120 |
4 | 2210321013103202230113 |
5 | 2441123020412011043 |
6 | 40033311521415023 |
7 | 2246442450036465 |
oct | 244710723425427 |
9 | 44107104664846 |
10 | 11331320032023 |
11 | 36796498298a2 |
12 | 133010419a473 |
13 | 642700c47894 |
14 | 2b2620179835 |
15 | 149b487dc983 |
hex | a4e474e2b17 |
11331320032023 has 16 divisors (see below), whose sum is σ = 15318496281600. Its totient is φ = 7449626479680.
The previous prime is 11331320032013. The next prime is 11331320032099. The reversal of 11331320032023 is 32023002313311.
11331320032023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11331320032023 - 25 = 11331320031991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11331320031984 and 11331320032002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11331320032003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 55887463 + ... + 56089848.
It is an arithmetic number, because the mean of its divisors is an integer number (957406017600).
Almost surely, 211331320032023 is an apocalyptic number.
11331320032023 is a deficient number, since it is larger than the sum of its proper divisors (3987176249577).
11331320032023 is a wasteful number, since it uses less digits than its factorization.
11331320032023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 111977782.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 11331320032023 its reverse (32023002313311), we get a palindrome (43354322345334).
The spelling of 11331320032023 in words is "eleven trillion, three hundred thirty-one billion, three hundred twenty million, thirty-two thousand, twenty-three".
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