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11331321122113 is a prime number
BaseRepresentation
bin1010010011100100011101…
…0111101100110101000001
31111010021010020210120021021
42210321013113230311001
52441123021201401423
640033312001025441
72246442462226546
oct244710727546501
944107106716237
1011331321122113
11367964a4038a3
121330104625281
13642701239ac5
142b2620380bcd
15149b4895595d
hexa4e475ecd41

11331321122113 has 2 divisors, whose sum is σ = 11331321122114. Its totient is φ = 11331321122112.

The previous prime is 11331321122101. The next prime is 11331321122137. The reversal of 11331321122113 is 31122112313311.

11331321122113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6434806302864 + 4896514819249 = 2536692^2 + 2212807^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331321122113 - 213 = 11331321113921 is a prime.

It is not a weakly prime, because it can be changed into another prime (11331321122413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665660561056 + 5665660561057.

It is an arithmetic number, because the mean of its divisors is an integer number (5665660561057).

Almost surely, 211331321122113 is an apocalyptic number.

It is an amenable number.

11331321122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331321122113 is an equidigital number, since it uses as much as digits as its factorization.

11331321122113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 648, while the sum is 25.

Adding to 11331321122113 its reverse (31122112313311), we get a palindrome (42453433435424).

The spelling of 11331321122113 in words is "eleven trillion, three hundred thirty-one billion, three hundred twenty-one million, one hundred twenty-two thousand, one hundred thirteen".