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11331321441457 is a prime number
BaseRepresentation
bin1010010011100100011101…
…1000111010110010110001
31111010021010021101210022211
42210321013120322302301
52441123021242111312
640033312011532121
72246442465026563
oct244710730726261
944107107353284
1011331321441457
11367964a601816
12133010475a041
1364270131c274
142b2620425333
15149b489ba3a7
hexa4e4763acb1

11331321441457 has 2 divisors, whose sum is σ = 11331321441458. Its totient is φ = 11331321441456.

The previous prime is 11331321441389. The next prime is 11331321441469. The reversal of 11331321441457 is 75414412313311.

11331321441457 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9172393731216 + 2158927710241 = 3028596^2 + 1469329^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331321441457 - 211 = 11331321439409 is a prime.

It is not a weakly prime, because it can be changed into another prime (11331321441257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665660720728 + 5665660720729.

It is an arithmetic number, because the mean of its divisors is an integer number (5665660720729).

Almost surely, 211331321441457 is an apocalyptic number.

It is an amenable number.

11331321441457 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331321441457 is an equidigital number, since it uses as much as digits as its factorization.

11331321441457 is an evil number, because the sum of its binary digits is even.

The product of its digits is 120960, while the sum is 40.

Adding to 11331321441457 its reverse (75414412313311), we get a palindrome (86745733754768).

The spelling of 11331321441457 in words is "eleven trillion, three hundred thirty-one billion, three hundred twenty-one million, four hundred forty-one thousand, four hundred fifty-seven".