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11331344131 = 24414642091
BaseRepresentation
bin10101000110110011…
…01001011100000011
31002020200220220221021
422203121221130003
5141201311003011
65112222010311
7550541556502
oct124331513403
932220826837
1011331344131
114895280618
122242a16997
1310b777b173
14796cc2839
15464be0471
hex2a3669703

11331344131 has 4 divisors (see below), whose sum is σ = 11335988664. Its totient is φ = 11326699600.

The previous prime is 11331344077. The next prime is 11331344153. The reversal of 11331344131 is 13144313311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11331344131 - 217 = 11331213059 is a prime.

It is a super-2 number, since 2×113313441312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11331344096 and 11331344105.

It is not an unprimeable number, because it can be changed into a prime (11331342131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2318605 + ... + 2323486.

It is an arithmetic number, because the mean of its divisors is an integer number (2833997166).

Almost surely, 211331344131 is an apocalyptic number.

11331344131 is a deficient number, since it is larger than the sum of its proper divisors (4644533).

11331344131 is an equidigital number, since it uses as much as digits as its factorization.

11331344131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4644532.

The product of its digits is 1296, while the sum is 25.

Adding to 11331344131 its reverse (13144313311), we get a palindrome (24475657442).

The spelling of 11331344131 in words is "eleven billion, three hundred thirty-one million, three hundred forty-four thousand, one hundred thirty-one".

Divisors: 1 2441 4642091 11331344131