Base | Representation |
---|---|
bin | 1010010011100100100010… |
… | …1111011110011101111011 |
3 | 1111010021011212002120211221 |
4 | 2210321020233132131323 |
5 | 2441123043044210323 |
6 | 40033314142132511 |
7 | 2246443161632632 |
oct | 244711057363573 |
9 | 44107155076757 |
10 | 11331344131963 |
11 | 367966139a4a9 |
12 | 1330110281137 |
13 | 642705c351bb |
14 | 2b2623450519 |
15 | 149b4a99d55d |
hex | a4e48bde77b |
11331344131963 has 2 divisors, whose sum is σ = 11331344131964. Its totient is φ = 11331344131962.
The previous prime is 11331344131949. The next prime is 11331344132029. The reversal of 11331344131963 is 36913144313311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331344131963 - 217 = 11331344000891 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331344132963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665672065981 + 5665672065982.
It is an arithmetic number, because the mean of its divisors is an integer number (5665672065982).
Almost surely, 211331344131963 is an apocalyptic number.
11331344131963 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331344131963 is an equidigital number, since it uses as much as digits as its factorization.
11331344131963 is an evil number, because the sum of its binary digits is even.
The product of its digits is 209952, while the sum is 43.
The spelling of 11331344131963 in words is "eleven trillion, three hundred thirty-one billion, three hundred forty-four million, one hundred thirty-one thousand, nine hundred sixty-three".
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