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11332213121323 is a prime number
BaseRepresentation
bin1010010011100111110010…
…0010011010000100101011
31111010100102102020211011001
42210321330202122010223
52441131333024340243
640033540303415431
72246503543133413
oct244717442320453
944110372224131
1011332213121323
113679a67971026
1213303132b4577
13642813c918a3
142b26a6a17643
15149b9be01a4d
hexa4e7c89a12b

11332213121323 has 2 divisors, whose sum is σ = 11332213121324. Its totient is φ = 11332213121322.

The previous prime is 11332213121233. The next prime is 11332213121401. The reversal of 11332213121323 is 32312131223311.

Together with previous prime (11332213121233) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11332213121323 - 213 = 11332213113131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11332213121291 and 11332213121300.

It is not a weakly prime, because it can be changed into another prime (11332219121323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666106560661 + 5666106560662.

It is an arithmetic number, because the mean of its divisors is an integer number (5666106560662).

Almost surely, 211332213121323 is an apocalyptic number.

11332213121323 is a deficient number, since it is larger than the sum of its proper divisors (1).

11332213121323 is an equidigital number, since it uses as much as digits as its factorization.

11332213121323 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3888, while the sum is 28.

Adding to 11332213121323 its reverse (32312131223311), we get a palindrome (43644344344634).

The spelling of 11332213121323 in words is "eleven trillion, three hundred thirty-two billion, two hundred thirteen million, one hundred twenty-one thousand, three hundred twenty-three".