Base | Representation |
---|---|
bin | 10101000110111010… |
… | …11001111111011001 |
3 | 1002020202202222111221 |
4 | 22203131121333121 |
5 | 141202034020213 |
6 | 5112255052041 |
7 | 550553132215 |
oct | 124335317731 |
9 | 32222688457 |
10 | 11332329433 |
11 | 4895893917 |
12 | 2243211021 |
13 | 10b7a34799 |
14 | 79709b945 |
15 | 464d3738d |
hex | 2a3759fd9 |
11332329433 has 2 divisors, whose sum is σ = 11332329434. Its totient is φ = 11332329432.
The previous prime is 11332329367. The next prime is 11332329487. The reversal of 11332329433 is 33492323311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6880370704 + 4451958729 = 82948^2 + 66723^2 .
It is an emirp because it is prime and its reverse (33492323311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11332329433 - 221 = 11330232281 is a prime.
It is not a weakly prime, because it can be changed into another prime (11332329133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666164716 + 5666164717.
It is an arithmetic number, because the mean of its divisors is an integer number (5666164717).
Almost surely, 211332329433 is an apocalyptic number.
It is an amenable number.
11332329433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332329433 is an equidigital number, since it uses as much as digits as its factorization.
11332329433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 34992, while the sum is 34.
The spelling of 11332329433 in words is "eleven billion, three hundred thirty-two million, three hundred twenty-nine thousand, four hundred thirty-three".
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