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113330102113 = 615118424663
BaseRepresentation
bin110100110001100000…
…0000001111101100001
3101211112011120200200101
41221203000001331201
53324100001231423
6124021345222401
711121265654654
oct1514300017541
9354464520611
10113330102113
1144076985118
1219b6a031a01
13a8c13bb827
1456b159789b
152e346447ad
hex1a63001f61

113330102113 has 4 divisors (see below), whose sum is σ = 113348532928. Its totient is φ = 113311671300.

The previous prime is 113330102069. The next prime is 113330102177. The reversal of 113330102113 is 311201033311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113330102113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (113330100113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9206181 + ... + 9218482.

It is an arithmetic number, because the mean of its divisors is an integer number (28337133232).

Almost surely, 2113330102113 is an apocalyptic number.

It is an amenable number.

113330102113 is a deficient number, since it is larger than the sum of its proper divisors (18430815).

113330102113 is an equidigital number, since it uses as much as digits as its factorization.

113330102113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18430814.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 113330102113 its reverse (311201033311), we get a palindrome (424531135424).

The spelling of 113330102113 in words is "one hundred thirteen billion, three hundred thirty million, one hundred two thousand, one hundred thirteen".

Divisors: 1 6151 18424663 113330102113