Base | Representation |
---|---|
bin | 1010010011101011011111… |
… | …1101101100111010010001 |
3 | 1111010102222220022012211121 |
4 | 2210322313331230322101 |
5 | 2441140403243211423 |
6 | 40034223241042241 |
7 | 2246540340444412 |
oct | 244726775547221 |
9 | 44112886265747 |
10 | 11333210132113 |
11 | 367a429732a91 |
12 | 1330551186381 |
13 | 6429426c32bc |
14 | 2b275d1c7809 |
15 | 149c096e245d |
hex | a4eb7f6ce91 |
11333210132113 has 2 divisors, whose sum is σ = 11333210132114. Its totient is φ = 11333210132112.
The previous prime is 11333210132071. The next prime is 11333210132141. The reversal of 11333210132113 is 31123101233311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10671675163009 + 661534969104 = 3266753^2 + 813348^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11333210132113 is a prime.
It is not a weakly prime, because it can be changed into another prime (11333210132173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666605066056 + 5666605066057.
It is an arithmetic number, because the mean of its divisors is an integer number (5666605066057).
Almost surely, 211333210132113 is an apocalyptic number.
It is an amenable number.
11333210132113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11333210132113 is an equidigital number, since it uses as much as digits as its factorization.
11333210132113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 11333210132113 its reverse (31123101233311), we get a palindrome (42456311365424).
The spelling of 11333210132113 in words is "eleven trillion, three hundred thirty-three billion, two hundred ten million, one hundred thirty-two thousand, one hundred thirteen".
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