Base | Representation |
---|---|
bin | 1010010011101011100010… |
… | …0011011110010111010011 |
3 | 1111010110000120221021200021 |
4 | 2210322320203132113103 |
5 | 2441140413312042003 |
6 | 40034224233204311 |
7 | 2246540520555040 |
oct | 244727043362723 |
9 | 44113016837607 |
10 | 11333220034003 |
11 | 367a43428646a |
12 | 1330554560697 |
13 | 64294477c2ca |
14 | 2b27606441c7 |
15 | 149c0a4eb2bd |
hex | a4eb88de5d3 |
11333220034003 has 8 divisors (see below), whose sum is σ = 13227831286272. Its totient is φ = 9507503736456.
The previous prime is 11333220033977. The next prime is 11333220034039. The reversal of 11333220034003 is 30043002233311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11333220034003 - 213 = 11333220025811 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11333220034063) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17223738325 + ... + 17223738982.
It is an arithmetic number, because the mean of its divisors is an integer number (1653478910784).
Almost surely, 211333220034003 is an apocalyptic number.
11333220034003 is a deficient number, since it is larger than the sum of its proper divisors (1894611252269).
11333220034003 is an equidigital number, since it uses as much as digits as its factorization.
11333220034003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34447477361.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 11333220034003 its reverse (30043002233311), we get a palindrome (41376222267314).
The spelling of 11333220034003 in words is "eleven trillion, three hundred thirty-three billion, two hundred twenty million, thirty-four thousand, three".
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