Base | Representation |
---|---|
bin | 10101000111000010… |
… | …10001011110010001 |
3 | 1002020211200111000221 |
4 | 22203201101132101 |
5 | 141202313434441 |
6 | 5112332513041 |
7 | 550564553452 |
oct | 124341213621 |
9 | 32224614027 |
10 | 11333343121 |
11 | 4896416481 |
12 | 224361b781 |
13 | 10b7ccacb9 |
14 | 797283129 |
15 | 464e878d1 |
hex | 2a3851791 |
11333343121 has 4 divisors (see below), whose sum is σ = 11492967744. Its totient is φ = 11173718500.
The previous prime is 11333343067. The next prime is 11333343157. The reversal of 11333343121 is 12134333311.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12134333311 = 110051 ⋅110261.
It is a cyclic number.
It is not a de Polignac number, because 11333343121 - 217 = 11333212049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11333343181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79812205 + ... + 79812346.
It is an arithmetic number, because the mean of its divisors is an integer number (2873241936).
Almost surely, 211333343121 is an apocalyptic number.
It is an amenable number.
11333343121 is a deficient number, since it is larger than the sum of its proper divisors (159624623).
11333343121 is an equidigital number, since it uses as much as digits as its factorization.
11333343121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 159624622.
The product of its digits is 1944, while the sum is 25.
Adding to 11333343121 its reverse (12134333311), we get a palindrome (23467676432).
The spelling of 11333343121 in words is "eleven billion, three hundred thirty-three million, three hundred forty-three thousand, one hundred twenty-one".
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