Base | Representation |
---|---|
bin | 11001110001001111000001… |
… | …101011001001011101001011 |
3 | 112212021200021202012200111002 |
4 | 121301033001223021131023 |
5 | 104323333130121300123 |
6 | 1041013101335525215 |
7 | 32605102556410340 |
oct | 3161170153113513 |
9 | 485250252180432 |
10 | 113334551353163 |
11 | 33125a05682198 |
12 | 10864bb3b2980b |
13 | 4b3152cc0bb1a |
14 | 1ddb5c8a5a7c7 |
15 | d18159ac3528 |
hex | 6713c1ac974b |
113334551353163 has 4 divisors (see below), whose sum is σ = 129525201546480. Its totient is φ = 97143901159848.
The previous prime is 113334551353081. The next prime is 113334551353237. The reversal of 113334551353163 is 361353155433311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 113334551353163 - 214 = 113334551336779 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (113334551353763) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8095325096648 + ... + 8095325096661.
It is an arithmetic number, because the mean of its divisors is an integer number (32381300386620).
Almost surely, 2113334551353163 is an apocalyptic number.
113334551353163 is a deficient number, since it is larger than the sum of its proper divisors (16190650193317).
113334551353163 is an equidigital number, since it uses as much as digits as its factorization.
113334551353163 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16190650193316.
The product of its digits is 2187000, while the sum is 47.
The spelling of 113334551353163 in words is "one hundred thirteen trillion, three hundred thirty-four billion, five hundred fifty-one million, three hundred fifty-three thousand, one hundred sixty-three".
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