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1133421225131 = 131427288721163
BaseRepresentation
bin10000011111100101001…
…010110110010010101011
311000100120001222220200202
4100133211022312102223
5122032221313201011
62224404142222415
7144613143311456
oct20374512662253
94010501886622
101133421225131
113a7754808108
121637b8584a0b
1382b5bbb8130
143cc0204649d
151e739b2623b
hex107e52b64ab

1133421225131 has 16 divisors (see below), whose sum is σ = 1221943666944. Its totient is φ = 1045090279584.

The previous prime is 1133421225119. The next prime is 1133421225191. The reversal of 1133421225131 is 1315221243311.

It is not a de Polignac number, because 1133421225131 - 210 = 1133421224107 is a prime.

It is a super-2 number, since 2×11334212251312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1133421225094 and 1133421225103.

It is not an unprimeable number, because it can be changed into a prime (1133421225191) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53546156 + ... + 53567318.

It is an arithmetic number, because the mean of its divisors is an integer number (76371479184).

Almost surely, 21133421225131 is an apocalyptic number.

1133421225131 is a deficient number, since it is larger than the sum of its proper divisors (88522441813).

1133421225131 is a wasteful number, since it uses less digits than its factorization.

1133421225131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25490.

The product of its digits is 4320, while the sum is 29.

Adding to 1133421225131 its reverse (1315221243311), we get a palindrome (2448642468442).

The spelling of 1133421225131 in words is "one trillion, one hundred thirty-three billion, four hundred twenty-one million, two hundred twenty-five thousand, one hundred thirty-one".

Divisors: 1 13 1427 2887 18551 21163 37531 275119 4119749 30199601 53556737 61097581 392594813 794268553 87186248087 1133421225131