Base | Representation |
---|---|
bin | 10000011111100101001… |
… | …010110110010010101011 |
3 | 11000100120001222220200202 |
4 | 100133211022312102223 |
5 | 122032221313201011 |
6 | 2224404142222415 |
7 | 144613143311456 |
oct | 20374512662253 |
9 | 4010501886622 |
10 | 1133421225131 |
11 | 3a7754808108 |
12 | 1637b8584a0b |
13 | 82b5bbb8130 |
14 | 3cc0204649d |
15 | 1e739b2623b |
hex | 107e52b64ab |
1133421225131 has 16 divisors (see below), whose sum is σ = 1221943666944. Its totient is φ = 1045090279584.
The previous prime is 1133421225119. The next prime is 1133421225191. The reversal of 1133421225131 is 1315221243311.
It is not a de Polignac number, because 1133421225131 - 210 = 1133421224107 is a prime.
It is a super-2 number, since 2×11334212251312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1133421225094 and 1133421225103.
It is not an unprimeable number, because it can be changed into a prime (1133421225191) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53546156 + ... + 53567318.
It is an arithmetic number, because the mean of its divisors is an integer number (76371479184).
Almost surely, 21133421225131 is an apocalyptic number.
1133421225131 is a deficient number, since it is larger than the sum of its proper divisors (88522441813).
1133421225131 is a wasteful number, since it uses less digits than its factorization.
1133421225131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25490.
The product of its digits is 4320, while the sum is 29.
Adding to 1133421225131 its reverse (1315221243311), we get a palindrome (2448642468442).
The spelling of 1133421225131 in words is "one trillion, one hundred thirty-three billion, four hundred twenty-one million, two hundred twenty-five thousand, one hundred thirty-one".
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