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113342240422402 = 256671120211201
BaseRepresentation
bin11001110001010110001011…
…111110100111101000000010
3112212022102010121112212120021
4121301112023332213220002
5104323444402022004102
61041020412331204054
732605464243413665
oct3161261376475002
9485272117485507
10113342240422402
11331291a098a772
121086659aba662a
134b32186bc7a34
141ddbb17d076dc
15d18459b51137
hex67158bfa7a02

113342240422402 has 4 divisors (see below), whose sum is σ = 170013360633606. Its totient is φ = 56671120211200.

The previous prime is 113342240422337. The next prime is 113342240422409. The reversal of 113342240422402 is 204224042243311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 72451062688761 + 40891177733641 = 8511819^2 + 6394621^2 .

It is a super-3 number, since 3×1133422404224023 (a number of 43 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (113342240422409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28335560105599 + ... + 28335560105602.

Almost surely, 2113342240422402 is an apocalyptic number.

113342240422402 is a deficient number, since it is larger than the sum of its proper divisors (56671120211204).

113342240422402 is an equidigital number, since it uses as much as digits as its factorization.

113342240422402 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56671120211203.

The product of its (nonzero) digits is 73728, while the sum is 34.

Adding to 113342240422402 its reverse (204224042243311), we get a palindrome (317566282665713).

The spelling of 113342240422402 in words is "one hundred thirteen trillion, three hundred forty-two billion, two hundred forty million, four hundred twenty-two thousand, four hundred two".

Divisors: 1 2 56671120211201 113342240422402