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1133441133001 is a prime number
BaseRepresentation
bin10000011111100110010…
…110110010100111001001
311000100121110110100011021
4100133212112302213021
5122032241412224001
62224410133032441
7144613504445062
oct20374626624711
94010543410137
101133441133001
113a7764a751a1
12163803185721
1382b63068638
143cc04949569
151e73b759ba1
hex107e65b29c9

1133441133001 has 2 divisors, whose sum is σ = 1133441133002. Its totient is φ = 1133441133000.

The previous prime is 1133441132963. The next prime is 1133441133017. The reversal of 1133441133001 is 1003311443311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 685948368400 + 447492764601 = 828220^2 + 668949^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1133441133001 is a prime.

It is not a weakly prime, because it can be changed into another prime (1133441133701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566720566500 + 566720566501.

It is an arithmetic number, because the mean of its divisors is an integer number (566720566501).

Almost surely, 21133441133001 is an apocalyptic number.

It is an amenable number.

1133441133001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133441133001 is an equidigital number, since it uses as much as digits as its factorization.

1133441133001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1133441133001 its reverse (1003311443311), we get a palindrome (2136752576312).

The spelling of 1133441133001 in words is "one trillion, one hundred thirty-three billion, four hundred forty-one million, one hundred thirty-three thousand, one".