Base | Representation |
---|---|
bin | 1010010011110000000011… |
… | …0000100101111011110001 |
3 | 1111010120011000101200220210 |
4 | 2210330000300211323301 |
5 | 2441200403421314213 |
6 | 40034544345454333 |
7 | 2246612530355634 |
oct | 244740060457361 |
9 | 44116130350823 |
10 | 11334431432433 |
11 | 367a9a6067a9a |
12 | 13308321a13a9 |
13 | 642aa8734a05 |
14 | 2b283749dc1b |
15 | 149c7ba390c3 |
hex | a4f00c25ef1 |
11334431432433 has 16 divisors (see below), whose sum is σ = 15120749376000. Its totient is φ = 7552201345920.
The previous prime is 11334431432417. The next prime is 11334431432437. The reversal of 11334431432433 is 33423413443311.
It is not a de Polignac number, because 11334431432433 - 24 = 11334431432417 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11334431432391 and 11334431432400.
It is not an unprimeable number, because it can be changed into a prime (11334431432437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60570093 + ... + 60756933.
It is an arithmetic number, because the mean of its divisors is an integer number (945046836000).
Almost surely, 211334431432433 is an apocalyptic number.
It is an amenable number.
11334431432433 is a deficient number, since it is larger than the sum of its proper divisors (3786317943567).
11334431432433 is a wasteful number, since it uses less digits than its factorization.
11334431432433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 197672.
The product of its digits is 373248, while the sum is 39.
Adding to 11334431432433 its reverse (33423413443311), we get a palindrome (44757844875744).
The spelling of 11334431432433 in words is "eleven trillion, three hundred thirty-four billion, four hundred thirty-one million, four hundred thirty-two thousand, four hundred thirty-three".
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