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11334431432437 is a prime number
BaseRepresentation
bin1010010011110000000011…
…0000100101111011110101
31111010120011000101200220221
42210330000300211323311
52441200403421314222
640034544345454341
72246612530355641
oct244740060457365
944116130350827
1011334431432437
11367a9a6067aa3
1213308321a13b1
13642aa8734a09
142b283749dc21
15149c7ba390c7
hexa4f00c25ef5

11334431432437 has 2 divisors, whose sum is σ = 11334431432438. Its totient is φ = 11334431432436.

The previous prime is 11334431432417. The next prime is 11334431432449. The reversal of 11334431432437 is 73423413443311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9374092617796 + 1960338814641 = 3061714^2 + 1400121^2 .

It is a cyclic number.

It is not a de Polignac number, because 11334431432437 - 219 = 11334430908149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11334431432393 and 11334431432402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11334431432417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5667215716218 + 5667215716219.

It is an arithmetic number, because the mean of its divisors is an integer number (5667215716219).

Almost surely, 211334431432437 is an apocalyptic number.

It is an amenable number.

11334431432437 is a deficient number, since it is larger than the sum of its proper divisors (1).

11334431432437 is an equidigital number, since it uses as much as digits as its factorization.

11334431432437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 870912, while the sum is 43.

Adding to 11334431432437 its reverse (73423413443311), we get a palindrome (84757844875748).

The spelling of 11334431432437 in words is "eleven trillion, three hundred thirty-four billion, four hundred thirty-one million, four hundred thirty-two thousand, four hundred thirty-seven".