Base | Representation |
---|---|
bin | 10101000111001111… |
… | …01101101000111001 |
3 | 1002020221212020212001 |
4 | 22203213231220321 |
5 | 141203232000403 |
6 | 5112433021001 |
7 | 550615114432 |
oct | 124347555071 |
9 | 32227766761 |
10 | 11335031353 |
11 | 4897369908 |
12 | 22440b4761 |
13 | 10b846c559 |
14 | 7975a2489 |
15 | 4651bcc1d |
hex | 2a39eda39 |
11335031353 has 2 divisors, whose sum is σ = 11335031354. Its totient is φ = 11335031352.
The previous prime is 11335031303. The next prime is 11335031399. The reversal of 11335031353 is 35313053311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11270582569 + 64448784 = 106163^2 + 8028^2 .
It is an emirp because it is prime and its reverse (35313053311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11335031353 - 29 = 11335030841 is a prime.
It is not a weakly prime, because it can be changed into another prime (11335031303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5667515676 + 5667515677.
It is an arithmetic number, because the mean of its divisors is an integer number (5667515677).
Almost surely, 211335031353 is an apocalyptic number.
It is an amenable number.
11335031353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11335031353 is an equidigital number, since it uses as much as digits as its factorization.
11335031353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6075, while the sum is 28.
Adding to 11335031353 its reverse (35313053311), we get a palindrome (46648084664).
The spelling of 11335031353 in words is "eleven billion, three hundred thirty-five million, thirty-one thousand, three hundred fifty-three".
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