11335130450131 has 4 divisors (see below), whose sum is σ = 11335348372312. Its totient is φ = 11334912527952.

The previous prime is 11335130450099. The next prime is 11335130450197. The reversal of 11335130450131 is 13105403153311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11335130450131 - 2⁵ = 11335130450099 is a prime.

It is a super-2 number, since 2×11335130450131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11335130450093 and 11335130450102.

It is not an unprimeable number, because it can be changed into a prime (11335130450731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 108883050 + ... + 108987103.

It is an arithmetic number, because the mean of its divisors is an integer number (2833837093078).

Almost surely, 2^{11335130450131} is an apocalyptic number.

11335130450131 is a deficient number, since it is larger than the sum of its proper divisors (217922181).

11335130450131 is an equidigital number, since it uses as much as digits as its factorization.

11335130450131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 217922180.

The product of its (nonzero) digits is 8100, while the sum is 31.

The spelling of 11335130450131 in words is "eleven trillion, three hundred thirty-five billion, one hundred thirty million, four hundred fifty thousand, one hundred thirty-one".