Base | Representation |
---|---|
bin | 1010010011110011000100… |
… | …1111110001001000100011 |
3 | 1111010122020201002200220202 |
4 | 2210330301033301020203 |
5 | 2441204040144124024 |
6 | 40035201205255415 |
7 | 2246641636000652 |
oct | 244746117611043 |
9 | 44118221080822 |
10 | 11335244911139 |
11 | 3680283274646 |
12 | 1330a1a70456b |
13 | 642ba8126966 |
14 | 2b28b3537199 |
15 | 149cc8174bae |
hex | a4f313f1223 |
11335244911139 has 2 divisors, whose sum is σ = 11335244911140. Its totient is φ = 11335244911138.
The previous prime is 11335244911099. The next prime is 11335244911163. The reversal of 11335244911139 is 93111944253311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11335244911139 - 232 = 11330949943843 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11335244911093 and 11335244911102.
It is not a weakly prime, because it can be changed into another prime (11335244911439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5667622455569 + 5667622455570.
It is an arithmetic number, because the mean of its divisors is an integer number (5667622455570).
Almost surely, 211335244911139 is an apocalyptic number.
11335244911139 is a deficient number, since it is larger than the sum of its proper divisors (1).
11335244911139 is an equidigital number, since it uses as much as digits as its factorization.
11335244911139 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 349920, while the sum is 47.
The spelling of 11335244911139 in words is "eleven trillion, three hundred thirty-five billion, two hundred forty-four million, nine hundred eleven thousand, one hundred thirty-nine".
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