Base | Representation |
---|---|
bin | 1010010011110011000101… |
… | …0001110001000111010011 |
3 | 1111010122020202002022222212 |
4 | 2210330301101301013103 |
5 | 2441204040312412342 |
6 | 40035201224422335 |
7 | 2246641643313161 |
oct | 244746121610723 |
9 | 44118222068885 |
10 | 11335245435347 |
11 | 36802835a2479 |
12 | 1330a1a9179ab |
13 | 642ba827b442 |
14 | 2b28b3632231 |
15 | 149cc822a182 |
hex | a4f314711d3 |
11335245435347 has 2 divisors, whose sum is σ = 11335245435348. Its totient is φ = 11335245435346.
The previous prime is 11335245435313. The next prime is 11335245435373. The reversal of 11335245435347 is 74353454253311.
It is a strong prime.
It is an emirp because it is prime and its reverse (74353454253311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11335245435347 - 232 = 11330950468051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11335245435295 and 11335245435304.
It is not a weakly prime, because it can be changed into another prime (11335245435307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5667622717673 + 5667622717674.
It is an arithmetic number, because the mean of its divisors is an integer number (5667622717674).
Almost surely, 211335245435347 is an apocalyptic number.
11335245435347 is a deficient number, since it is larger than the sum of its proper divisors (1).
11335245435347 is an equidigital number, since it uses as much as digits as its factorization.
11335245435347 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 9072000, while the sum is 50.
Adding to 11335245435347 its reverse (74353454253311), we get a palindrome (85688699688658).
The spelling of 11335245435347 in words is "eleven trillion, three hundred thirty-five billion, two hundred forty-five million, four hundred thirty-five thousand, three hundred forty-seven".
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