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1133525130281 is a prime number
BaseRepresentation
bin10000011111101011010…
…111001101110000101001
311000100211022111211202122
4100133223113031300221
5122032424413132111
62224422333241025
7144615544430105
oct20375327156051
94010738454678
101133525130281
113a77a8426635
12163827333175
1382b7759827b
143cc11b72905
151e743ceccdb
hex107eb5cdc29

1133525130281 has 2 divisors, whose sum is σ = 1133525130282. Its totient is φ = 1133525130280.

The previous prime is 1133525130217. The next prime is 1133525130301. The reversal of 1133525130281 is 1820315253311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 827117491600 + 306407638681 = 909460^2 + 553541^2 .

It is a cyclic number.

It is not a de Polignac number, because 1133525130281 - 26 = 1133525130217 is a prime.

It is a super-2 number, since 2×11335251302812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1133525130781) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566762565140 + 566762565141.

It is an arithmetic number, because the mean of its divisors is an integer number (566762565141).

Almost surely, 21133525130281 is an apocalyptic number.

It is an amenable number.

1133525130281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133525130281 is an equidigital number, since it uses as much as digits as its factorization.

1133525130281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 35.

The spelling of 1133525130281 in words is "one trillion, one hundred thirty-three billion, five hundred twenty-five million, one hundred thirty thousand, two hundred eighty-one".