Base | Representation |
---|---|
bin | 10000100000000100011… |
… | …100010110001111101001 |
3 | 11000101220122021110202012 |
4 | 100200010130112033221 |
5 | 122034310122444103 |
6 | 2224532204045305 |
7 | 144632144111654 |
oct | 20400434261751 |
9 | 4011818243665 |
10 | 1133945906153 |
11 | 3a79a39a1795 |
12 | 163924233835 |
13 | 82c13802188 |
14 | 3cc519c489b |
15 | 1e76ac172d8 |
hex | 108047163e9 |
1133945906153 has 2 divisors, whose sum is σ = 1133945906154. Its totient is φ = 1133945906152.
The previous prime is 1133945906147. The next prime is 1133945906167. The reversal of 1133945906153 is 3516095493311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 936110430784 + 197835475369 = 967528^2 + 444787^2 .
It is a cyclic number.
It is not a de Polignac number, because 1133945906153 - 240 = 34434278377 is a prime.
It is a super-2 number, since 2×11339459061532 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1133945906173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566972953076 + 566972953077.
It is an arithmetic number, because the mean of its divisors is an integer number (566972953077).
Almost surely, 21133945906153 is an apocalyptic number.
It is an amenable number.
1133945906153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133945906153 is an equidigital number, since it uses as much as digits as its factorization.
1133945906153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1312200, while the sum is 50.
The spelling of 1133945906153 in words is "one trillion, one hundred thirty-three billion, nine hundred forty-five million, nine hundred six thousand, one hundred fifty-three".
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