Base | Representation |
---|---|
bin | 1010010100000100111010… |
… | …1101000111101010000011 |
3 | 1111011002121110211022121021 |
4 | 2211001032231013222003 |
5 | 2441243342213042011 |
6 | 40041312330410311 |
7 | 2250201421353034 |
oct | 245011655075203 |
9 | 44132543738537 |
10 | 11340034112131 |
11 | 368231069319a |
12 | 1331936590997 |
13 | 64348c3b9aba |
14 | 2b2c09604a8b |
15 | 149ea883c471 |
hex | a504eb47a83 |
11340034112131 has 16 divisors (see below), whose sum is σ = 12273077698560. Its totient is φ = 10445610276640.
The previous prime is 11340034112087. The next prime is 11340034112161. The reversal of 11340034112131 is 13121143004311.
It is a cyclic number.
It is not a de Polignac number, because 11340034112131 - 213 = 11340034103939 is a prime.
It is a super-2 number, since 2×113400341121312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11340034112096 and 11340034112105.
It is not an unprimeable number, because it can be changed into a prime (11340034112161) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21939775 + ... + 22450696.
It is an arithmetic number, because the mean of its divisors is an integer number (767067356160).
Almost surely, 211340034112131 is an apocalyptic number.
11340034112131 is a deficient number, since it is larger than the sum of its proper divisors (933043586429).
11340034112131 is a wasteful number, since it uses less digits than its factorization.
11340034112131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44390906.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 11340034112131 its reverse (13121143004311), we get a palindrome (24461177116442).
The spelling of 11340034112131 in words is "eleven trillion, three hundred forty billion, thirty-four million, one hundred twelve thousand, one hundred thirty-one".
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