113404354433 has 4 divisors (see below), whose sum is σ = 113405410260. Its totient is φ = 113403298608.

The previous prime is 113404354373. The next prime is 113404354439. The reversal of 113404354433 is 334453404311.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 97283481409 + 16120873024 = 311903^2 + 126968^2 .

It is a cyclic number.

It is not a de Polignac number, because 113404354433 - 2¹² = 113404350337 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113404354393 and 113404354402.

It is not an unprimeable number, because it can be changed into a prime (113404354439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345878 + ... + 588591.

It is an arithmetic number, because the mean of its divisors is an integer number (28351352565).

Almost surely, 2^113404354433 is an apocalyptic number.

It is an amenable number.

113404354433 is a deficient number, since it is larger than the sum of its proper divisors (1055827).

113404354433 is an equidigital number, since it uses as much as digits as its factorization.

113404354433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1055826.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 113404354433 its reverse (334453404311), we get a palindrome (447857758744).

The spelling of 113404354433 in words is "one hundred thirteen billion, four hundred four million, three hundred fifty-four thousand, four hundred thirty-three".