Base | Representation |
---|---|
bin | 11001110010010110100010… |
… | …101000101110000100001010 |
3 | 112212120000111021122212011220 |
4 | 121302112202220232010022 |
5 | 104331112411022044224 |
6 | 1041112241135502510 |
7 | 32613461505420330 |
oct | 3162264250560412 |
9 | 485500437585156 |
10 | 113411340034314 |
11 | 3315552a904953 |
12 | 10877a64387a36 |
13 | 4b3884994116a |
14 | 20011d1101b50 |
15 | d1a1511aa279 |
hex | 6725a2a2e10a |
113411340034314 has 64 divisors (see below), whose sum is σ = 259715255095296. Its totient is φ = 32342124556224.
The previous prime is 113411340034229. The next prime is 113411340034351. The reversal of 113411340034314 is 413430043114311.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 51919209 + ... + 54059475.
It is an arithmetic number, because the mean of its divisors is an integer number (4058050860864).
Almost surely, 2113411340034314 is an apocalyptic number.
113411340034314 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
113411340034314 is an abundant number, since it is smaller than the sum of its proper divisors (146303915060982).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113411340034314 is a wasteful number, since it uses less digits than its factorization.
113411340034314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2142659.
The product of its (nonzero) digits is 20736, while the sum is 33.
Adding to 113411340034314 its reverse (413430043114311), we get a palindrome (526841383148625).
The spelling of 113411340034314 in words is "one hundred thirteen trillion, four hundred eleven billion, three hundred forty million, thirty-four thousand, three hundred fourteen".
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