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113411340034351 is a prime number
BaseRepresentation
bin11001110010010110100010…
…101000101110000100101111
3112212120000111021122212020021
4121302112202220232010233
5104331112411022044401
61041112241135503011
732613461505420412
oct3162264250560457
9485500437585207
10113411340034351
113315552a904987
1210877a64387a67
134b38849941198
1420011d1101b79
15d1a1511aa2a1
hex6725a2a2e12f

113411340034351 has 2 divisors, whose sum is σ = 113411340034352. Its totient is φ = 113411340034350.

The previous prime is 113411340034229. The next prime is 113411340034367. The reversal of 113411340034351 is 153430043114311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113411340034351 - 223 = 113411331645743 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113411340034651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56705670017175 + 56705670017176.

It is an arithmetic number, because the mean of its divisors is an integer number (56705670017176).

Almost surely, 2113411340034351 is an apocalyptic number.

113411340034351 is a deficient number, since it is larger than the sum of its proper divisors (1).

113411340034351 is an equidigital number, since it uses as much as digits as its factorization.

113411340034351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 34.

Adding to 113411340034351 its reverse (153430043114311), we get a palindrome (266841383148662).

The spelling of 113411340034351 in words is "one hundred thirteen trillion, four hundred eleven billion, three hundred forty million, thirty-four thousand, three hundred fifty-one".