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1134130019417 is a prime number
BaseRepresentation
bin10000100000001111011…
…010101011110001011001
311000102101110201101122222
4100200033122223301121
5122040144241110132
62225002342153425
7144636541051223
oct20401732536131
94012343641588
101134130019417
113a7a8891380a
12163975a22875
1382c429b6335
143cc6c22d413
151e77be84412
hex1080f6abc59

1134130019417 has 2 divisors, whose sum is σ = 1134130019418. Its totient is φ = 1134130019416.

The previous prime is 1134130019317. The next prime is 1134130019423. The reversal of 1134130019417 is 7149100314311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1130232639376 + 3897380041 = 1063124^2 + 62429^2 .

It is a cyclic number.

It is not a de Polignac number, because 1134130019417 - 218 = 1134129757273 is a prime.

It is not a weakly prime, because it can be changed into another prime (1134130019017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567065009708 + 567065009709.

It is an arithmetic number, because the mean of its divisors is an integer number (567065009709).

Almost surely, 21134130019417 is an apocalyptic number.

It is an amenable number.

1134130019417 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134130019417 is an equidigital number, since it uses as much as digits as its factorization.

1134130019417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 35.

The spelling of 1134130019417 in words is "one trillion, one hundred thirty-four billion, one hundred thirty million, nineteen thousand, four hundred seventeen".