Base | Representation |
---|---|
bin | 10101000111111111… |
… | …01111111101101011 |
3 | 1002021101201101011121 |
4 | 22203333233331223 |
5 | 141211340113311 |
6 | 5113220040111 |
7 | 551022506560 |
oct | 124377577553 |
9 | 32241641147 |
10 | 11341332331 |
11 | 489a98292a |
12 | 2246233037 |
13 | 10b9867544 |
14 | 798362867 |
15 | 465a14b71 |
hex | 2a3feff6b |
11341332331 has 4 divisors (see below), whose sum is σ = 12961522672. Its totient is φ = 9721141992.
The previous prime is 11341332329. The next prime is 11341332347. The reversal of 11341332331 is 13323314311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11341332331 - 21 = 11341332329 is a prime.
It is a super-2 number, since 2×113413323312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11341332296 and 11341332305.
It is not an unprimeable number, because it can be changed into a prime (11341338331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 810095160 + ... + 810095173.
It is an arithmetic number, because the mean of its divisors is an integer number (3240380668).
Almost surely, 211341332331 is an apocalyptic number.
11341332331 is a deficient number, since it is larger than the sum of its proper divisors (1620190341).
11341332331 is an equidigital number, since it uses as much as digits as its factorization.
11341332331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1620190340.
The product of its digits is 1944, while the sum is 25.
Adding to 11341332331 its reverse (13323314311), we get a palindrome (24664646642).
The spelling of 11341332331 in words is "eleven billion, three hundred forty-one million, three hundred thirty-two thousand, three hundred thirty-one".
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