113413334134137 has 4 divisors (see below), whose sum is σ = 151217778845520. Its totient is φ = 75608889422756.

The previous prime is 113413334134127. The next prime is 113413334134181. The reversal of 113413334134137 is 731431433314311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 113413334134137 - 2⁶ = 113413334134073 is a prime.

It is a super-3 number, since 3×113413334134137³ (a number of 43 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (113413334134127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18902222355687 + ... + 18902222355692.

It is an arithmetic number, because the mean of its divisors is an integer number (37804444711380).

Almost surely, 2^{113413334134137} is an apocalyptic number.

It is an amenable number.

113413334134137 is a deficient number, since it is larger than the sum of its proper divisors (37804444711383).

113413334134137 is an equidigital number, since it uses as much as digits as its factorization.

113413334134137 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37804444711382.

The product of its digits is 326592, while the sum is 42.

Adding to 113413334134137 its reverse (731431433314311), we get a palindrome (844844767448448).

The spelling of 113413334134137 in words is "one hundred thirteen trillion, four hundred thirteen billion, three hundred thirty-four million, one hundred thirty-four thousand, one hundred thirty-seven".