Base | Representation |
---|---|
bin | 10000100000001111101… |
… | …011011100110000011011 |
3 | 11000102101202222200101202 |
4 | 100200033223130300123 |
5 | 122040201402224423 |
6 | 2225003020304415 |
7 | 144636623314406 |
oct | 20401753346033 |
9 | 4012352880352 |
10 | 1134134414363 |
11 | 3a7a903457a5 |
12 | 1639773a210b |
13 | 82c438948b2 |
14 | 3cc6ca54d3d |
15 | 1e77c551728 |
hex | 1080fadcc1b |
1134134414363 has 2 divisors, whose sum is σ = 1134134414364. Its totient is φ = 1134134414362.
The previous prime is 1134134414311. The next prime is 1134134414383. The reversal of 1134134414363 is 3634144314311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1134134414363 - 216 = 1134134348827 is a prime.
It is not a weakly prime, because it can be changed into another prime (1134134414383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567067207181 + 567067207182.
It is an arithmetic number, because the mean of its divisors is an integer number (567067207182).
Almost surely, 21134134414363 is an apocalyptic number.
1134134414363 is a deficient number, since it is larger than the sum of its proper divisors (1).
1134134414363 is an equidigital number, since it uses as much as digits as its factorization.
1134134414363 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 124416, while the sum is 38.
Adding to 1134134414363 its reverse (3634144314311), we get a palindrome (4768278728674).
The spelling of 1134134414363 in words is "one trillion, one hundred thirty-four billion, one hundred thirty-four million, four hundred fourteen thousand, three hundred sixty-three".
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