1134140330131 has 4 divisors (see below), whose sum is σ = 1134143059192. Its totient is φ = 1134137601072.

The previous prime is 1134140330129. The next prime is 1134140330159. The reversal of 1134140330131 is 1310330414311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1134140330131 - 2¹ = 1134140330129 is a prime.

It is a super-2 number, since 2×1134140330131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1134140330096 and 1134140330105.

It is not an unprimeable number, because it can be changed into a prime (1134140337131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 597405 + ... + 1620238.

It is an arithmetic number, because the mean of its divisors is an integer number (283535764798).

Almost surely, 2^{1134140330131} is an apocalyptic number.

1134140330131 is a deficient number, since it is larger than the sum of its proper divisors (2729061).

1134140330131 is an equidigital number, since it uses as much as digits as its factorization.

1134140330131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2729060.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1134140330131 its reverse (1310330414311), we get a palindrome (2444470744442).

The spelling of 1134140330131 in words is "one trillion, one hundred thirty-four billion, one hundred forty million, three hundred thirty thousand, one hundred thirty-one".