1134166062131 has 4 divisors (see below), whose sum is σ = 1134170336712. Its totient is φ = 1134161787552.

The previous prime is 1134166062097. The next prime is 1134166062143. The reversal of 1134166062131 is 1312606614311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1134166062131 - 2¹⁰ = 1134166061107 is a prime.

It is a super-2 number, since 2×1134166062131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1134166062091 and 1134166062100.

It is not an unprimeable number, because it can be changed into a prime (1134166062431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1710950 + ... + 2279403.

It is an arithmetic number, because the mean of its divisors is an integer number (283542584178).

Almost surely, 2^{1134166062131} is an apocalyptic number.

1134166062131 is a deficient number, since it is larger than the sum of its proper divisors (4274581).

1134166062131 is an equidigital number, since it uses as much as digits as its factorization.

1134166062131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4274580.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 1134166062131 in words is "one trillion, one hundred thirty-four billion, one hundred sixty-six million, sixty-two thousand, one hundred thirty-one".